(PHP 4, PHP 5, PHP 7, PHP 8)
is_resource — Finds whether a variable is a resource
value
The variable being evaluated.
Returns true
if value
is a resource,
false
otherwise.
Example #1 is_resource() example
<?php
$handle = fopen("php://stdout", "w");
if (is_resource($handle)) {
echo '$handle is a resource';
}
?>
The above example will output:
$handle is a resource
Note:
is_resource() is not a strict type-checking method: it will return
false
ifvalue
is a resource variable that has been closed.